# Write a system of linear inequalities that has no solution system

On the other side, there are no solutions.

### Solving systems of linear inequalities worksheet answers

Slope is 2 again. It has the exact same slope as this other line. On the graph, you can see that the points B and N provide possible solutions for the system because their coordinates will make both inequalities true statements. Values that are true for one equation but not all of them do not solve the system. Let me graph a couple more points here just so that I make sure that I'm drawing it reasonably accurately. When the graphs of a system of two linear equations are parallel to each other, we found that there was no solution to the system. The graph will now look like this: This system of inequalities has no points in common so has no solution. We could do the x is greater than 1. Identifying Solutions In order to figure out whether a given point is a solution for a system of inequalities, we can look to see whether it lies within the common region for that system. Is the point a solution of both inequalities? This area up here satisfies the last one and the first one. The ordered pair 3,1 made one inequality true, but the other one false.

They're separated by this kind of no-man's land between these two parallel lines. Determine whether the ordered pair is a solution to the system. But as you can see, their solutions sets are completely non-overlapping. And that's the region of the x, y coordinate plane that will satisfy all of them. There's no solution set or the solution set of the system is empty. You can verify whether a point is a solution to a system of linear inequalities in the same way you verify whether a point is a solution to a system of equations. In this case, it is shown as a dashed line as the points on the line do not satisfy the inequality.

In contrast, points M and A both lie outside the shared bounded region. So 2x minus 5, the y-intercept is negative 5. On one side lie all the solutions to the inequality. If we move forward 2, we'll move up 4, just like that.

Authored by: James Sousa Mathispower4u.

### Write a system of linear inequalities to define the profit regions.

The second inequality is y is less than 2x minus 5. Graph If you missed this problem, review Figure. Solve the inequality If you missed this problem, review Figure. We could do the x is greater than 1. The following example shows how to test a point to see whether it is a solution to a system of inequalities. Note how they have the same slopes. But once again, there's nothing that satisfies all three of these. The colored area, the area on the plane that contains all possible solutions to an inequality, is called the bounded region. For any x, this is 2x minus 5, and we care about the y's that are less than that. This area up here satisfies the last one and the first one. A system of two linear inequalities is shown below. The solution of a system of linear inequalities is shown as a shaded region in the x-y coordinate system that includes all the points whose ordered pairs make the inequalities true. Authored by: James Sousa Mathispower4u. Empty set.
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